((x^2-2x-3)/(x^2+2x-3))((4x-4)/(x+1))

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Solution for ((x^2-2x-3)/(x^2+2x-3))((4x-4)/(x+1)) equation: 


D( x )

x+1 = 0

x^2+2*x-3 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x^2+2*x-3 = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

x in (-oo:-3) U (-3:-1) U (-1:1) U (1:+oo)

((x^2-(2*x)-3)/(x^2+2*x-3))*((4*x-4)/(x+1)) = 0

((x^2-2*x-3)/(x^2+2*x-3))*((4*x-4)/(x+1)) = 0

((x^2-2*x-3)*(4*x-4))/((x^2+2*x-3)*(x+1)) = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

(x+1)*(x-3) = 0

x^2+2*x-3 = 0

x^2+2*x-3 = 0

DELTA = 2^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-2)/(1*2) or x = (-16^(1/2)-2)/(1*2)

x = 1 or x = -3

(x+3)*(x-1) = 0

((x-3)*(4*x-4))/((x+3)*(x-1)) = 0

( 4*x-4 )

4*x-4 = 0 // + 4

4*x = 4 // : 4

x = 4/4

x = 1

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 1} 

x = 3

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